There Are 9 Red And 6 Green Marbles

There s one blue marble.

There are 9 red and 6 green marbles.

Indeed we have these equations where r is the number of red marbles g is the number. There are 9 red and 6 green marbles in a bag. The measure of probability is number of favourable outcomes total possible outcomes a favourable outcome is a green marble of which there are 6. There s two green marbles in the bag.

In a jar of red green and blue marbles all but 6 are red marbles all but 8 are green and all but 4 are blue. In the bag there are 6 green marbles and 12 red marbles. So i could pick that red marble or that red marble. So this is all the possible outcomes.

What is the probability of that child getting a green marble. There are a total of 14 green and blue marbles so the probability is 14 25 or 56. What percent of the marbles aren t blue. 9 blue marbles 8 green marbles 4 red marbles 8 white marbles and 6 yellow marbles.

Remember there is one less marble in the jar and that you assume the marble picked was green. As both requirements have to be fulfilled the required probability is the multiplication of both 6 15 6 15. What is the probability of drawing a green marble from the bag. Jun 21 2018 1 3 explanation.

You wish to know t probability that the single chosen green or blue marble. There are 6 red 4 green 5 blue and 5 yellow marbles in a jar. 1 answer jim g. At this moment the bag becomes the same as it is before a green marble is drawn i e.

Be careful letting children play with marbles they may swallow. There s two red marbles in the bag. 4 20 then find the probability of picking green again 3 19. The total number of marbles in the box is 25 that is 9 green 5 blue and 11 red.

7 red 5 green 6 blue pick 7 6 1 14 marbles and at least 1 is red because 14 green blue 11 at least 1 is blue because 14 red green 12 at least 1 is green because 14 red blue 13 picking 13 marbles could result in green marble absence if all 13 marbl. There are still 6 green marbles and 9 red ones. These are clearly all yellow. A child reaches in the bag and randomly takes one marble.

Write the probability as a fraction in simplest form a decimal and a percent. Solution from the condition we can determine how many marbles of each color were there in the jar. If we are too draw another green marble the same probability 6 15 will be resulted. So i could pick that green marble or that green marble.

Finally multiply the probabilities and reduce to get 3 95 share.